# How do you find the vertex and intercepts for #y = (x + 3)^2 – 4#?

##### 3 Answers

Vertex

#### Explanation:

Set

Add 4 to both sides

Square root both sides

Subtract 3 from both sides

You may if you so choose determine the vertex from this point

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Given

Vertex

**Vertex is at** **y intercept is**

**x intercepts are at**

#### Explanation:

Comparing with vertex form of equation

here

y intercept is found by putting

So y intercept is

x intercepts are found by putting

x intercepts are at

graph{(x+3)^2-4 [-10, 10, -5, 5]} [Ans]

Vertex =

y-intercept =

x-intercepts =

#### Explanation:

First, expand

The x-vertex of a quadratic equation

Plugging in

Now we plug in

So our vertex is

To find the y-intercept of a quadratic equation, plug in

To find the x-intercept of a quadratic equation, plug in

So our y-intercept is